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Question

a^{2} - 6 a + 1 = 0

হলে

a + \frac{1}{a} = ?

\sqrt{3}

3 \sqrt{3}

ANSWER : 3

Descrption

<pre>
দেওয়া আছে,
<math xmlns = "http://www.w3.org/1998/Math/MathML"><msup><mi>a</mi><mn>2</mn></msup><mo> - </mo><mn>6</mn><mi>a</mi><mo>  +  </mo><mn>1</mn><mo> = </mo><mn>0</mn><mo>&#xA0;</mo><mspace linebreak = "newline"/><mo>&#x21D2;</mo><msup><mi>a</mi><mn>2</mn></msup><mo>  +  </mo><mn>1</mn><mo> = </mo><mn>6</mn><mi>a</mi><mspace linebreak = "newline"/><mo>&#x21D2;</mo><mfrac><mrow><msup><mi>a</mi><mn>2</mn></msup><mo>  +  </mo><mn>1</mn></mrow><mi>a</mi></mfrac><mo> = </mo><mfrac><mrow><mn>6</mn><mi>a</mi></mrow><mi>a</mi></mfrac><mspace linebreak = "newline"/><mo>&#x21D2;</mo><mfrac><msup><mi>a</mi><mn>2</mn></msup><mi>a</mi></mfrac><mo>  +  </mo><mfrac><mn>1</mn><mi>a</mi></mfrac><mo> = </mo><mn>6</mn><mspace linebreak = "newline"/><mo>&#x21D2;</mo><mi>a</mi><mo>  +  </mo><mfrac><mn>1</mn><mi>a</mi></mfrac><mo> = </mo><mn>6</mn><mspace linebreak = "newline"/><mo>.</mo><mo>'</mo><mo>.</mo><mo>&#xA0;</mo><mi>a</mi><mo>  +  </mo><mfrac><mn>1</mn><mi>a</mi></mfrac><mo> = </mo><mn>6</mn></math>
</pre>

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