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Question
A box contains 21 balls numbered 1 to 21 . A ball numbered 1 to 21 . A ball is drawn and then another ball is brawn without replacement . What is the probability that both balls are even numbered?
2/7
3/14
8/21
5/21
ANSWER : 2
Descrption
<pre> There are 10 even number in the group 1 - 21 ∴ The probability that the first ball is even numbed <math xmlns = "http://www.w3.org/1998/Math/MathML"><mfrac><mn>10</mn><mn>21</mn></mfrac></math> And the probability that the second ball is even numbered <math xmlns = "http://www.w3.org/1998/Math/MathML"><mfrac><mn>9</mn><mn>20</mn></mfrac></math> ∴ Required probability = <math xmlns = "http://www.w3.org/1998/Math/MathML"><mspace linebreak = "newline"/><mo> = </mo><mfrac><mn>10</mn><mn>21</mn></mfrac><mo>×</mo><mfrac><mn>9</mn><mn>20</mn></mfrac><mspace linebreak = "newline"/><mo> = </mo><mfrac><mn>90</mn><mn>420</mn></mfrac><mspace linebreak = "newline"/><mo> = </mo><mfrac><mn>3</mn><mn>14</mn></mfrac></math> </pre>
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