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একটি সমান্তর অনুক্রমে সাধারণ অন্তর 10 এবং 6-তম পদটি 52 হলে 15-তম পদটি--
140
142
148
150
ANSWER : 2
Descrption
প্রথম পদ a ও সাধারণ অন্তর d হলে। r - তম পদ = a + (r - 1)d অতএব 6 - তম '' a = a + (6 - 1)d = > 52 = a + 5 <math xmlns = "http://www.w3.org/1998/Math/MathML"><mo>×</mo></math>10 = > a = 52 - 50 অতএব a = 2 অতএব 15 - তম পদ = 2 + (15 - 1) <math xmlns = "http://www.w3.org/1998/Math/MathML"><mo>×</mo></math>10 = 2 + 140 = 142
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