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Question

A 270 m long train running at the speed of 120 km /hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 seconds. What is the length of the other train?

230 m

240 m

260 m

320 m

ANSWER : 1

Descrption

<pre>
Relative speed 
 = 120  +  80 = 200 km 
200km  = 200
<math xmlns = "http://www.w3.org/1998/Math/MathML"><mo>&#xD7;</mo><mn>1000</mn><mo> = </mo><mn>200000</mn><mi>m</mi><mspace linebreak = "newline"/><mn>60</mn><mo>&#xA0;</mo><mi>m</mi><mi>i</mi><mi>n</mi><mo>&#xA0;</mo><mo> = </mo><mn>60</mn><mo>&#xD7;</mo><mn>60</mn><mo> = </mo><mn>3600</mn><mo>&#xA0;</mo><mi>s</mi><mi>e</mi><mi>c</mi><mspace linebreak = "newline"/><mn>3600</mn><mo>&#xA0;</mo><mi>s</mi><mi>e</mi><mi>c</mi><mo>&#xA0;</mo><mo> = </mo><mn>200000</mn><mi>m</mi><mspace linebreak = "newline"/><mn>1</mn><mo>&#xA0;</mo><mo>"</mo><mo>&#xA0;</mo><mo> = </mo><mfrac><mn>200000</mn><mn>3600</mn></mfrac><mspace linebreak = "newline"/><mn>9</mn><mo>&#xA0;</mo><mo>"</mo><mo>&#xA0;</mo><mo>&#xA0;</mo><mo>&#xA0;</mo><mo> = </mo><mfrac><mrow><mn>200000</mn><mo>&#xD7;</mo><mn>9</mn></mrow><mn>3600</mn></mfrac><mspace linebreak = "newline"/><mo> = </mo><mn>500</mn><mo>&#xA0;</mo><mi>m</mi><mspace linebreak = "newline"/><mi>T</mi><mi>h</mi><mi>e</mi><mo>&#xA0;</mo><mi>l</mi><mi>e</mi><mi>n</mi><mi>g</mi><mi>t</mi><mi>h</mi><mo>&#xA0;</mo><mi>o</mi><mi>f</mi><mo>&#xA0;</mo><mi>o</mi><mi>t</mi><mi>h</mi><mi>e</mi><mi>r</mi><mo>&#xA0;</mo><mi>t</mi><mi>r</mi><mi>a</mi><mi>i</mi><mi>n</mi><mo>&#xA0;</mo><mspace linebreak = "newline"/><mo> = </mo><mo>(</mo><mn>500</mn><mo> - </mo><mn>270</mn><mo>)</mo><mi>m</mi><mspace linebreak = "newline"/><mo> = </mo><mn>230</mn><mo>&#xA0;</mo><mi>m</mi><mo>&#xA0;</mo></math>
</pre>

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