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Question

If a man swims 4 miters upstream at 1 mph and back downstream to the same point at 4 mph, what is his average speed?

0.8 mph

1.6 mph

2.4 mph

3.2 mph

ANSWER : 2

Descrption

Let towards upstream he swims at v1 mph and towards downstream he swims at v2 mph . '. v1 = 1 and v2  =  4  Now, his average speed <math xmlns = "http://www.w3.org/1998/Math/MathML"><mo> = </mo><mfrac><mn>2</mn><mstyle displaystyle = "true"><mfrac><mn>1</mn><msub><mi>v</mi><mn>1</mn></msub></mfrac><mo>  +  </mo><mfrac><mn>1</mn><msub><mi>v</mi><mn>2</mn></msub></mfrac></mstyle></mfrac><mo> = </mo><mfrac><mn>2</mn><mstyle displaystyle = "true"><mfrac><mn>1</mn><mn>1</mn></mfrac><mo>  +  </mo><mfrac><mn>1</mn><mn>4</mn></mfrac></mstyle></mfrac><mspace linebreak = "newline"/><mo> = </mo><mfrac><mn>2</mn><mstyle displaystyle = "true"><mn>1</mn><mo>  +  </mo><mfrac><mn>1</mn><mn>4</mn></mfrac></mstyle></mfrac><mo> = </mo><mfrac><mn>2</mn><mstyle displaystyle = "true"><mfrac><mn>5</mn><mn>4</mn></mfrac></mstyle></mfrac><mo> = </mo><mfrac><mn>2</mn><mstyle displaystyle = "true"><mfrac><mn>5</mn><mn>4</mn></mfrac></mstyle></mfrac><mo> = </mo><mn>2</mn><mo>  ×  </mo><mfrac><mn>4</mn><mn>3</mn></mfrac><mo> = </mo><mfrac><mn>8</mn><mn>5</mn></mfrac><mo> = </mo><mn>1</mn><mo>.</mo><mn>6</mn><mo> </mo><mi>m</mi><mi>p</mi><mi>h</mi><mspace linebreak = "newline"/><mo>[</mo><mi>R</mi><mi>u</mi><mi>l</mi><mi>e</mi><mo> </mo><mi>o</mi><mi>f</mi><mo> </mo><mi>h</mi><mi>a</mi><mi>r</mi><mi>m</mi><mi>o</mi><mi>n</mi><mi>i</mi><mi>c</mi><mo> </mo><mi>m</mi><mi>e</mi><mi>a</mi><mi>n</mi><mo> </mo><mo>]</mo><mspace linebreak = "newline"/><mi>T</mi><mi>o</mi><mi>t</mi><mi>a</mi><mi>l</mi><mo> </mo><mn>5</mn><mo> </mo><mi>m</mi><mi>p</mi><mi>h</mi><mo> </mo><mi>s</mi><mi>w</mi><mi>i</mi><mi>m</mi><mi>s</mi><mo> </mo><mn>8</mn><mo> </mo><mi>m</mi><mi>i</mi><mi>t</mi><mi>r</mi><mi>e</mi><mi>s</mi><mo> </mo><mspace linebreak = "newline"/><mo> </mo><mn>5</mn><mfenced open = "|" close = "|"><mn>8</mn></mfenced><mo> </mo><mn>1</mn><mo>.</mo><mn>6</mn><mo> </mo><mi>m</mi><mi>p</mi><mi>h</mi><mspace linebreak = "newline"/><mfrac><mrow><mo> </mo><mn>5</mn></mrow><mstyle displaystyle = "true"><mfrac><mn>30</mn><mstyle displaystyle = "true"><mfrac><mn>30</mn><mo>  ×  </mo></mfrac></mstyle></mfrac></mstyle></mfrac></math>

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