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Question
Two small circular parks of diameter 16 meter and 12 meter are to be replaced by a bigger circular park. What would be the radius of this new park, if the new park has to occupy the same space as the two small parks?
20 meter
15 meter
10 meter
100 meter
ANSWER : 3
Descrption
<p> </p><p>We know,</p><p>Area of circle, A = πr²</p><p> </p><p> diameter of first circle = 16m </p><p> <strong>∴</strong> radius = <math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mrow><mn>16</mn><mo> </mo></mrow><mn>2</mn></mfrac><mi>m</mi></math> = 8m </p><p> <strong>∴</strong> Area of first circle, A₁ = π x 8²= π x 64 = 201m²</p><p> diameter of second circle = 12m </p><p> <strong>∴ </strong>radius = <math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mrow><mn>12</mn><mo> </mo></mrow><mn>2</mn></mfrac><mi>m</mi></math> = 6m </p><p> </p><p>Area of second circle, A₂ = π x 6²= π x 36 = 113m²</p><p>Sum of two circle, </p><p>201m² + 113m² = 314m²</p><p>According to question, Large Circle:</p><p>314= πr²</p><p>r² = <math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mrow><mn>314</mn><mo> </mo></mrow><mi>π</mi></mfrac></math></p><p>r² =<math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mrow><mn>314</mn><mo> </mo></mrow><mn>3.14</mn></mfrac></math> [<strong>∵ </strong>π = 3.14]</p><p>r² = 100</p><p>r = √100</p><p>r = 10m</p>
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