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Question

How may seconds will a 500 meter long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr ?

ANSWER : 2

Descrption

Here, Train Long is= 500m.Train Speed is =<math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mrow><mn>63</mn><mo>*</mo><mn>1000</mn></mrow><mn>3600</mn></mfrac></math>=17.5 m/sec.Man Velocity is=<math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mrow><mn>3</mn><mo>*</mo><mn>1000</mn></mrow><mn>3600</mn></mfrac></math>=0.83 m/secwe know, t=<math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mi>s</mi><mi>v</mi></mfrac></math>so,Time required for Train pass 500m is=<math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mn>500</mn><mrow><mn>17</mn><mo>.</mo><mn>5</mn></mrow></mfrac></math>=28.57 Sec28.57 Sec Man pass the distance is= 0.83 X 28.57= 23.81 mTime Required for Train to pass 23.81 m distance is =&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mrow><mn>23</mn><mo>.</mo><mn>81</mn></mrow><mrow><mn>17</mn><mo>.</mo><mn>5</mn></mrow></mfrac></math>=1.36 SecSo, Time required for train to pass the man is= 28.57+1.36=29.93 say 30.00 Sec.Ans: 30 sec&nbsp;&nbsp;&nbsp;Relative speed = 63 - 3 = 60 km/hr60 * 5/18 = 50/3 m/secTime = Distance / speedTime = 500 / (50/3 ) = 30 sec

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