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Question
30
°
C
তাপমাত্রায় 740 m m চাপে 25 ml গ্যাসে কয়টি অণু খাকে?
5
.
306
×
10
20
6
.
023
×
10
23
5
.
894
×
10
20
2
.
62
×
10
22
ANSWER : 3
Descrption
<p style="margin-left:0px;">P = 740 mmHg = 740 / 760 atm</p><p style="margin-left:0px;">V = 25 ml = .025 L</p><p style="margin-left:0px;">T = (30 + 273) K = 303 K </p><p style="margin-left:0px;">R = 0.0821 L atm/K mol</p><p style="margin-left:0px;">n = (P × V) / (R × T) = (740/760 atm × .025 L) / (0.0821 L atm/K mol × 303 K) = 9.785 x 10<sup>-4</sup> mol</p><p style="margin-left:0px;">গ্যাস মোলার সংখ্যা হলোঃ</p><p style="margin-left:0px;">N = n × N<sub>A</sub></p><p style="margin-left:0px;">যেখানে, N<sub>A</sub> হল আবদ্ধ অণুগুলির সংখ্যা এক মোলে। N<sub>A</sub> এর মান 6.022 × 10<sup>23</sup> হলে, এখন সমস্যাটি সমাধান করতে পারি।</p><p style="margin-left:0px;">N = (9.785 × 10<sup>-4</sup> mol) × (6.022 × 10<sup>23</sup> mol) = 5.894 x 10<sup>20</sup></p><p style="margin-left:0px;">তাই, 740 mm চাপে 25 ml গ্যাসে 5.894 x 10<sup>20</sup> অণু থাকে।</p>
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