The sum of the squares of three numbers is 138, while the sum of their products taken two at a time is 131. Their sum is –
Created: 1 year ago |
Updated: 10 months ago
best des
a2 + b2 + c2 = 138
ab + ac + bc = 131
a + b + c = ?
Now, we know,
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2ac + 2bc
=> (a + b + c)2 = 138 + 2×131
=> (a + b + c)2 = 400
=> a + b + c = √400
=> a + b + c = 20
Ans. 20
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