A woman says, "If you reverse the digits my age, the figures represent my husband's age. He is senior to me and the defference between our ages is one-eleventh of their sum. "What is her age now?
Created: 6 years ago |
Updated: 2 years ago
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Let, the unit's digit of woman's age be 'y' and ten's digit be 'x'
If so, the woman's age is = (10x + y) years and her husband’s age is = (10y + x) years. [Digits are reversed]
ATQ,
(10y + x) - (10x + y) = (10y + x) + (10x + y) (1/11)
or, 9y - 9x = (11y + 11x)/11
or, 9y - 9x = 11(y + x)/11
or, 9y - y = x + 9x
or, 10x = 8y
or, x = (4/5)y
Clearly, y should be a single digit and multiple of 5, which is 5 [only possible value]
Hence, y = 5 and x = 4
So, woman's age = (10x + y) = 45 years.
Md Azizur Rahman
Founder of Satt
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