Three taps A, B and C can fill a tank in 12,25 and 20 hours respectively. If a is open all the time and B and C are open for one hour each alternately, the tank will be full in :
Created: 6 years ago |
Updated: 3 years ago
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A + B s 1 hour work = ( 1/12 + 1/15) = 3/20
A + C s hours work = ( 1/12 + 1/20) = 2/15
Part filled in 2 hrs = ( 3/20 + 2/15) = 17/60
part filled 6 hrs = (3× 17/60) = 17/20
Remaining part = ( 1 - 17/20) = 3/20
Now, it is the turn of A and B and 3/20 part is filled by A and B in 1 hour
Total time taken to fill the tank = ( 6 + 1) = 7 hrs
Md Azizur Rahman
Founder of Satt
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