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Let, first, second and third cars are c1, c2 be c3 respectively.
Distance covered by c1 : c3 = (240 - 80) : (240 + 80)
=160 : 320 = 1 : 2
Here, we know speed is directly proportional to the distance covered by these cars as time is constant.
∴Ratio of speeds of c1 : c2 = 1 : 2 Again, at first meeting of all three cars as times are in arithmetic progression, speed is in harmonic mean. So, c2's speed = 2×1×21+2=43 ∴Ratio of speed = 1 : 43 : 2= 3: 4 : 6 Then of time = 13 : 14 16 = 4 : 3 : 2 ∴ Difference between the speed of c1 and c3=2402-2404=120-60=60 kmph.
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