A shopkeeper sells two shirts at the same price. He makes 10% profit on one and loses 10 the other. How much in percentage does he gain or lose?

Question

Satt Academy · Accepted Answer

Let, cost price of first shirt = x Tk. Cost price of second shirty= y Tk. According to the question,

x+x×10%=y-y×10% ⇒x+10x100=y-10y100 ⇒x+x10=y-y10 ⇒10x+x10=10y-y10 ⇒11x=9y ⇒11x=9y  [Multiplying 10 by both sides] ⇒xy=911That means cost price of first shirt 9 Tk. & second shirt 11 Tk. Total cost 9+11=20 Tk. Now at 10% profit on first shirt the selling price will be = 9 + 9× 10% = 9.9 Tk At 10% loss on second shirt the selling price will be= 11-11×10%= 9.9 Tk Total selling price will be = 9.9 + 9.9 = 19.8 Tk Loss amount = 20 - 19.8 = 0.2Tk  Percentage of loss = 0.220×100=1%loss  1% (Ans)