দেখাও যে, $g\left(y^{-2}\right)=g\left(y^2\right).$  

দেওয়া আছে , $f\left(x\right)=x^3-6x^2+11x-6$

$\therefore f\left(2\right)=2^3-6(2{)}^2+11\times 2-6$

$=8-24+22-6=30-30-0$

এবং $f\left(3\right)=(3{)}^3-6(3{)}^2+11\times 3-6$

                  $=27-54+33-6=60-60=0$

                  $\therefore f\left(2\right) = f\left(3\right)$ (দেখানো হলো)

দেওয়া আছে, $f\left(x\right)=x^3-6x^2+11x-6$

এখন, $f\left(x\right) = 0$

বা, $x^3-6x^2+11x-6=0$

বা $x^3-x^2-5x^2+5x+6x-6=0$

বা $x^2(x-1)-5x(x-1)+6(x-1)=0$

বা, $(x-1)(x^2-5x+6)=0$

বা, $(x-1)(x^2-2x-3x+6)=0$

বা, $(x-1)\left\{x\right(x-2)-3(x-2\left)\right\}=0$

বা, $(x - 1)(x - 2)(x - 3) = 0$

হয়, $x - 1 = 0$

$\therefore x = 1$                      অথবা, $x - 2 = 0$                         অথবা, $x - 3 = 0$

                                                        $\therefore x = 2$                                             x = 3

অতএব, x এর মান 1 বা 2 বা 3 এরূ জন্য f(x) = 0 হবে।