"নিচের সার্কিট হতে Vo এবং সমস্ত সার্কিটের মোট power loss নির্ণয় কর।"
Given :
Current source = 3A
Voltage source = 12V
Resistors : 4Ω, 2Ω, 8Ω, 3Ω
Let V1 and V2 =Vo
From KCL :
_________ (i)
______ (ii)
Solve (1) & (2) :
,
Power Loss in Resistors
4Ω : = 27.04W
2Ω :
8Ω :
3Ω :
= 9.6V = 9.6V
Total Power Loss = 40.8 W
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Maximum Power Transfer Theorem :
In electrical engineering, the maximum power transfer theorem states that, to obtain maximum external power from a power source with internal resistance, the resistance of the load must equal the resistance of the source as viewed from its output terminals.
Let Impedance of,
Xc near the terminal X is Z1=-j10
10 ohm resistance, Z2=10
3 ohm resistance, Z3=3
XL, Z4 =j14
Xc near to source, Z5=-j10
Now,
Zth=[Z5 || (Z3 +Z4) ] + Z2 +Z1
= [ -j10 || (3+j4)] + 100- j10
= 112 - j36
For t<0, the switch is closed.
Capacitor acts as open to DC.
Voltage across the capacitor,
v(0-)= {(12||4)×V}÷{(12||4)+6} = 8VFor t=0, the switch is opened,Voltage across the Capacitor cannot change instantaneously,So, v(0-)= v(0) = 8VAt t>0, The capacitor is discharging.Rth = (12||4) = 3 ohmC= 1/6 FTime constant, Π = Rth×C = 0.5 So, v(t) = v(0)e-t/Π = 8e-t/0.5 =8e-2t V (Ans.)
The initial energy stored in the Capacitor,
W=(1/2)CVo2
= 0.5×0.167×82
= 5.333J (Ans)
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