A 3-phase, 10 kVA, 400 V, 50 Hz, Y-connected alternator supplies the rated load at 0.8 power factor lagging . Given,  Ra = 0.5Ω  Xs = 10O Ω Find:

(a) The power angle (δ)

(b) The voltage regulation

Updated: 7 months ago
উত্তরঃ

Given, 3-phase, 10 kVA, 400 V, Y-connected, Ra = 0.5 Ω, Xs = 10 Ω, load 0.8 pf lag

Per-phase values, Vϕ=4003231 V, Ia

= 10,0003.400 14.43 Α, φ = 36.87°

Synchronous EMF,

Ea = Vϕ + laRa + jXs

Zs = 0.5+j10 ≈ 10.012587.13°

IaZs = 14.43-36.87° × 10.012587.13° ≈ 144.550.26°

Ea=231+j0 + 92.3+j110.9 = 9 = 323.3+j110.9

|Ea l ≈ 341.9 V, δ = tan-1(110.9/323.3) ≈ 18.9°

Voltage regulation, VR

|Ea|-VϕVϕ×100 341.9-231231 × 100 ≈ 48%

Md Zahid Hasan
Md Zahid Hasan
7 months ago
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Thevenin's theorem is a fundamental concept in circuit analysis that simplifies complex linear circuits into a simple equivalent circuit at a pair of terminals. This equivalent circuit consists of a single voltage source (Thevenin Voltage, VTh) in series with a single resistor (Thevenin Resistance, RTh). This simplification is particularly useful for analyzing how a specific load component behaves when connected to the complex circuit.

To determine the Thevenin's equivalent circuit at terminal X-Y, follow these steps:

        
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    To find VTh, analyze the circuit with the terminals open. You can use various circuit analysis techniques such as Kirchhoff's Voltage Law (KVL), Kirchhoff's Current Law (KCL), nodal analysis, or mesh analysis.     
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  •         Step 3: Calculate the Thevenin Resistance (RTh) or Equivalent Resistance (REQ).         
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For t<0, the switch is closed.

Capacitor acts as open to DC.

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     v(0-)= {(12||4)×V}÷{(12||4)+6} = 8VFor t=0, the switch is opened,Voltage across the Capacitor cannot change instantaneously,So, v(0-)= v(0) = 8VAt t>0, The capacitor is discharging.Rth = (12||4) = 3 ohmC= 1/6 FTime constant, Π = Rth×C = 0.5 So, v(t) = v(0)e-t/Π  = 8e-t/0.5 =8e-2t V (Ans.)

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