A 3-phase, 400 V, 50 Hz, 4-pole, Y-connected induction motor has the following data, $R_2$ = 0.1 $\Omega$ $X_2$ = 0.9 $\Omega$ per phase. The ratio of stator to rotor turns is $\frac{N_1}{N_2}=3.5$

Calculate: (a) The gross output at a slip of 5%.

(b) The maximum torque in synchronous watts.

Maximum Power Transfer Theorem :

In electrical engineering, the maximum power transfer theorem states that, to obtain maximum external power from a power source with internal resistance, the resistance of the load must equal the resistance of the source as viewed from its output terminals.

For t<0, the switch is closed.

Capacitor acts as open to DC.

Voltage across the capacitor,

     v(0^-)= {(12||4)×V}÷{(12||4)+6} = 8VFor t=0, the switch is opened,Voltage across the Capacitor cannot change instantaneously,So, v(0^-)= v(0) = 8VAt t>0, The capacitor is discharging.R_th = (12||4) = 3 ohmC= 1/6 FTime constant, Π = R_th×C = 0.5 So, v(t) = v(0)e^-t/Π  = 8e^-t/0.5 =8e^-2t V (Ans.)