A alone can do a piece of work in 30 days, while B alone can do it in 15 days and C alone can do it in 10 days. If in every second day B and in every third day C help A in doing the work, how many days still be required to complete the whole work?

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Satt Academy · Accepted Answer

LCM of 2 and 3 is 6Work done in first 6 days =

630+315+210=6+6+630=1830=415Remaining work = 1-35=5-35=25Next 3 days work done by them= 330+115+110=3+2+330=830=415Remaining work after 9 days = 25-415=6-415=215In 10th days, B will help A, thus work done by them after 9 days= 130+115=1+230=330=110Remaining work= 215-110=4-330=130In 11th days, A alone can do 13 part of work which is the amount of remaining work.Total 11 days will be required to complete the whole work. ans.

A alone can do a piece of work in 30 days, while B alone can do it in 15 days and C alone can do it in 10 days. If in every second day B and in every third day C help A in doing the work, how many days still be required to complete the whole work? (work and time)

Question: A alone can do a piece of work in 30 days, while B alone can do it in 15 days and C alone can do it in 10 days. If in every second day B and in every third day C help A in doing the work, how many days still be required to complete the whole work? (work and time)

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