A person running an 800 meter race average 130 meters per minute for the first  34 of the race. The average speed for the remainder of the race is 145 meters per minute. What is the 3 person's average speed for the entire 800 meters rounded so the nearest whole numbered?

Updated: 10 months ago
āωāĻ¤ā§āϤāϰāσ
542

āĻ—ā§œ āĻ—āϤāĻŋāĻŦ⧇āĻ— (Average Speed)

āϕ⧋āύ⧋ āĻŦāĻ¸ā§āϤ⧁ āĻŽā§‹āϟ āϝ⧇ āĻĻā§‚āϰāĻ¤ā§āĻŦ āĻ…āϤāĻŋāĻ•ā§āϰāĻŽ āĻ•āϰ⧇, āϤāĻžāϕ⧇ āĻŽā§‹āϟ āϏāĻŽā§Ÿ āĻĻāĻŋā§Ÿā§‡ āĻ­āĻžāĻ— āĻ•āϰāϞ⧇ āĻ—ā§œ āĻ—āϤāĻŋāĻŦ⧇āĻ— āĻĒāĻžāĻ“ā§ŸāĻž āϝāĻžā§ŸāĨ¤

āϏāĻ‚āĻœā§āĻžāĻž

āĻ—ā§œ āĻ—āϤāĻŋāĻŦ⧇āĻ— āĻšāϞ⧋ āĻŽā§‹āϟ āĻ…āϤāĻŋāĻ•ā§āϰāĻžāĻ¨ā§āϤ āĻĻā§‚āϰāĻ¤ā§āĻŦ āĻ“ āĻŽā§‹āϟ āϏāĻŽā§Ÿā§‡āϰ āĻ…āύ⧁āĻĒāĻžāϤāĨ¤

āϏ⧂āĻ¤ā§āϰ

Average Speed = Total Distance Total Time

āĻ…āĻ°ā§āĻĨāĻžā§Ž,

v = d t

āĻāĻ–āĻžāύ⧇,
v = āĻ—ā§œ āĻ—āϤāĻŋāĻŦ⧇āĻ—
d = āĻŽā§‹āϟ āĻĻā§‚āϰāĻ¤ā§āĻŦ
t = āĻŽā§‹āϟ āϏāĻŽā§Ÿ

āωāĻĻāĻžāĻšāϰāĻŖ ā§§

āĻāĻ•āϟāĻŋ āĻ—āĻžā§œāĻŋ 120 km āĻĒāĻĨ 3 āϘāĻŖā§āϟāĻžā§Ÿ āĻ…āϤāĻŋāĻ•ā§āϰāĻŽ āĻ•āϰāϞāĨ¤

āĻ—ā§œ āĻ—āϤāĻŋāĻŦ⧇āĻ— =

120 Ãˇ 3 = 40 km/h

āωāĻĻāĻžāĻšāϰāĻŖ ⧍

āĻāĻ•āϜāύ āĻŦā§āϝāĻ•ā§āϤāĻŋ āĻĒā§āϰāĻĨāĻŽā§‡ 60 km āĻĒāĻĨ 30 km/h āĻŦ⧇āϗ⧇ āĻāĻŦāĻ‚ āĻĒāϰ⧇ 40 km āĻĒāĻĨ 20 km/h āĻŦ⧇āϗ⧇ āĻ…āϤāĻŋāĻ•ā§āϰāĻŽ āĻ•āϰāϞ⧇āύāĨ¤

āĻĒā§āϰāĻĨāĻŽ āĻ…āĻ‚āĻļ⧇āϰ āϏāĻŽā§Ÿ = 60 Ãˇ 30 = 2 āϘāĻŖā§āϟāĻž
āĻĻā§āĻŦāĻŋāĻ¤ā§€ā§Ÿ āĻ…āĻ‚āĻļ⧇āϰ āϏāĻŽā§Ÿ = 40 Ãˇ 20 = 2 āϘāĻŖā§āϟāĻž

āĻŽā§‹āϟ āĻĻā§‚āϰāĻ¤ā§āĻŦ = 60 + 40 = 100 km
āĻŽā§‹āϟ āϏāĻŽā§Ÿ = 2 + 2 = 4 āϘāĻŖā§āϟāĻž

āĻ—ā§œ āĻ—āϤāĻŋāĻŦ⧇āĻ— = 100 Ãˇ 4 = 25 km/h

āϏāĻŽāĻžāύ āĻĻā§‚āϰāĻ¤ā§āĻŦ⧇ āĻ—ā§œ āĻ—āϤāĻŋāĻŦ⧇āĻ—

āϝāĻĻāĻŋ āϏāĻŽāĻžāύ āĻĻā§‚āϰāĻ¤ā§āĻŦ āĻĻ⧁āχāϟāĻŋ āĻ­āĻŋāĻ¨ā§āύ āĻŦ⧇āϗ⧇ āĻ…āϤāĻŋāĻ•ā§āϰāĻŽ āĻ•āϰāĻž āĻšā§Ÿ, āϤāĻŦ⧇:

Average Speed = 2 xy x + y

āĻāĻ–āĻžāύ⧇ x āĻ“ y āĻšāϞ⧋ āĻĻ⧁āχāϟāĻŋ āĻŦ⧇āĻ—āĨ¤

āωāĻĻāĻžāĻšāϰāĻŖ ā§Š

āĻāĻ•āϟāĻŋ āĻ—āĻžā§œāĻŋ āϏāĻŽāĻžāύ āĻĻā§‚āϰāĻ¤ā§āĻŦ 40 km/h āĻ“ 60 km/h āĻŦ⧇āϗ⧇ āϚāϞāϞāĨ¤

āĻ—ā§œ āĻ—āϤāĻŋāĻŦ⧇āĻ— =

2 × 40 × 60 40 + 60

= 48 km/h

āϗ⧁āϰ⧁āĻ¤ā§āĻŦāĻĒā§‚āĻ°ā§āĻŖ āϤāĻĨā§āϝ

â€ĸ Average speed ≠ average of speeds (āϏāĻŦāϏāĻŽā§Ÿ āύ⧟)
â€ĸ āĻŽā§‹āϟ āĻĻā§‚āϰāĻ¤ā§āĻŦ āĻ“ āĻŽā§‹āϟ āϏāĻŽā§Ÿ āĻŦā§āϝāĻŦāĻšāĻžāϰ āĻ•āϰāϤ⧇ āĻšā§Ÿ
â€ĸ āĻāĻ•āĻ• āϏāĻžāϧāĻžāϰāĻŖāϤ km/h āĻŦāĻž m/s āĻšā§Ÿ

āĻŽāύ⧇ āϰāĻžāĻ–āĻžāϰ āĻ•ā§ŒāĻļāϞ

â€ĸ Average Speed = Total Distance Ãˇ Total Time
â€ĸ Equal distance → Harmonic Mean formula

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āωāĻ¤ā§āϤāϰāσ

Let, the speed of the train during returning journey be x kmph 

Speed during onward journey=  (x+ 25% of x)=x+ 25x100=5x4 kmph 

Distance covered in onward journey = 8002=400 km

Time taken by the train on onward journey= 4005x4 hours [As, time= Distance/Speed]

And time by the train in returning journey = 400x hours

According to the question,

4005x4+400x =16⇒4001×45x+400x=16⇒320x+400x=16⇒320+400x=16⇒16x=720 âˆ´x=45 kmph 

Speed of the train in the onward journey=5x4=5×454=56.25 kmph 

Tamanna
Tamanna
2 years ago
1.3k
āωāĻ¤ā§āϤāϰāσ

āĻĒā§āϰāĻļā§āύ⧇ āĻŦāϞāĻž āĻšāĻšā§āϛ⧇, 800 āĻŽāĻŋāϟāĻžāϰ āĻāĻ•āϟāĻŋ āĻĻ⧌⧜ āĻĒā§āϰāϤāĻŋāϝ⧋āĻ—āĻŋāϤāĻžā§Ÿ āĻāĻ• āĻŦā§āϝāĻ•ā§āϤāĻŋ 34āĻ…āĻ‚āĻļ āĻĒāĻĨ 130 āĻŽāĻŋāϟāĻžāϰ/ āĻŽāĻŋāύāĻŋāϟ āĻāĻŦāĻ‚ āĻĒāϰāĻŦāĻ°ā§āϤ⧀ āĻĒāĻĨ 145 āĻŽāĻŋāϟāĻžāϰ/ āĻŽāĻŋāύāĻŋāϟ āĻŦ⧇āϗ⧇ āϗ⧇āϞ⧇ āĻŽā§‹āϟ āĻĻā§Œā§œā§‡ āϤāĻžāϰ āĻ—ā§œ āĻ—āϤāĻŋāĻŦ⧇āĻ— āĻ•āϤ āĻ›āĻŋāϞ?

Here, first part of race = 800×12= 400 meter

∴ Second part of race = 800-400 = 400 meter

Time taken to cross first half of race

=400130 As, v =dt

=4013 meter/minute

Again, Time taken to cross second part of race = 400145=8029meter/minute

∴ Average speed =8004013+8029=8003.07 + 2.76

=8005.83=8006 [nearest whole of 5.83 is 6]

= 133.333 meter per minute

= 133 meter per minute (Approximately)

Najjar Hossain Raju
Najjar Hossain Raju
10 months ago
190
āωāĻ¤ā§āϤāϰāσ

āĻŽā§‹āϟ āϏāĻŽā§Ÿ āĻ¨ā§‡ā§Ÿ ā§Š āϘāĻŖā§āϟāĻž

āϝāĻžāĻ¤ā§āϰāĻž āĻŦāĻŋāϰāϤāĻŋ ā§§ āϘāĻŖā§āϟāĻž

āύāĻŋāϟ āϏāĻŽā§Ÿ āĻ¨ā§‡ā§Ÿ = ā§­ - ā§§ = ā§Ŧ āϘāĻŖā§āϟāĻž

āĻŽā§‹āϟ āĻĻā§‚āϰāĻ¤ā§āĻŦ = ā§Šā§Šā§Ļ āĻ•āĻŋ.āĻŽāĻŋ

∴ āĻ—ā§œ āĻ—āϤāĻŋāĻŦ⧇āĻ— āĻ•āĻŋ.āĻŽāĻŋ/ āϘāĻŖā§āϟāĻž = ā§Ģā§Ģ āĻ•āĻŋ.āĻŽāĻŋ / āϘāĻŖā§āϟāĻž

229
āĻļāĻŋāĻ•ā§āώāĻ•āĻĻ⧇āϰ āϜāĻ¨ā§āϝ āĻŦāĻŋāĻļ⧇āώāĻ­āĻžāĻŦ⧇ āϤ⧈āϰāĻŋ

ā§§ āĻ•ā§āϞāĻŋāϕ⧇ āĻĒā§āϰāĻļā§āύ, āĻļā§€āϟ, āϏāĻžāĻœā§‡āĻļāύ āĻ“
āĻ…āύāϞāĻžāχāύ āĻĒāϰ⧀āĻ•ā§āώāĻž āϤ⧈āϰāĻŋāϰ āϏāĻĢāϟāĻ“āϝāĻŧā§āϝāĻžāϰ!

āĻļ⧁āϧ⧁ āĻĒā§āϰāĻļā§āύ āϏāĻŋāϞ⧇āĻ•ā§āϟ āĻ•āϰ⧁āύ — āĻĒā§āϰāĻļā§āύāĻĒāĻ¤ā§āϰ āĻ…āĻŸā§‹āĻŽā§‡āϟāĻŋāĻ• āϤ⧈āϰāĻŋ!

āĻĒā§āϰāĻļā§āύ āĻāĻĄāĻŋāϟ āĻ•āϰāĻž āϝāĻžāĻŦ⧇
āϜāϞāĻ›āĻžāĻĒ āĻĻ⧇āϝāĻŧāĻž āϝāĻžāĻŦ⧇
āĻ āĻŋāĻ•āĻžāύāĻž āϝ⧁āĻ•ā§āϤ āĻ•āϰāĻž āϝāĻžāĻŦ⧇
Logo, Motto āϝ⧁āĻ•ā§āϤ āĻšāĻŦ⧇
āĻ…āĻŸā§‹ āĻĒā§āϰāϤāĻŋāĻˇā§āĻ āĻžāύ⧇āϰ āύāĻžāĻŽ
āĻ…āĻŸā§‹ āϏāĻŽāϝāĻŧ, āĻĒā§‚āĻ°ā§āĻŖāĻŽāĻžāύ
āĻĒā§āϰāĻļā§āύ āĻāĻĄāĻŋāϟ āĻ•āϰāĻž āϝāĻžāĻŦ⧇
āϜāϞāĻ›āĻžāĻĒ āĻĻ⧇āϝāĻŧāĻž āϝāĻžāĻŦ⧇
āĻ āĻŋāĻ•āĻžāύāĻž āϝ⧁āĻ•ā§āϤ āĻ•āϰāĻž āϝāĻžāĻŦ⧇
Logo, Motto āϝ⧁āĻ•ā§āϤ āĻšāĻŦ⧇
āĻ…āĻŸā§‹ āĻĒā§āϰāϤāĻŋāĻˇā§āĻ āĻžāύ⧇āϰ āύāĻžāĻŽ
āĻ…āĻŸā§‹ āϏāĻŽāϝāĻŧ, āĻĒā§‚āĻ°ā§āĻŖāĻŽāĻžāύ
āĻ…āĻŸā§‹ āύāĻŋāĻ°ā§āĻĻ⧇āĻļāύāĻž (āĻāĻĄāĻŋāϟāϝ⧋āĻ—ā§āϝ)
āĻ…āĻŸā§‹ āĻŦāĻŋāώāϝāĻŧ āĻ“ āĻ…āĻ§ā§āϝāĻžāϝāĻŧ
OMR āϏāĻ‚āϝ⧁āĻ•ā§āϤ āĻ•āϰāĻž āϝāĻžāĻŦ⧇
āĻĢāĻ¨ā§āϟ, āĻ•āϞāĻžāĻŽ, āĻĄāĻŋāĻ­āĻžāχāĻĄāĻžāϰ
āĻĒā§āϰāĻļā§āύ/āĻ…āĻĒāĻļāύ āĻ¸ā§āϟāĻžāχāϞ āĻĒāϰāĻŋāĻŦāĻ°ā§āϤāύ
āϏ⧇āϟ āϕ⧋āĻĄ, āĻŦāĻŋāώāϝāĻŧ āϕ⧋āĻĄ
āĻ…āĻŸā§‹ āύāĻŋāĻ°ā§āĻĻ⧇āĻļāύāĻž (āĻāĻĄāĻŋāϟāϝ⧋āĻ—ā§āϝ)
āĻ…āĻŸā§‹ āĻŦāĻŋāώāϝāĻŧ āĻ“ āĻ…āĻ§ā§āϝāĻžāϝāĻŧ
OMR āϏāĻ‚āϝ⧁āĻ•ā§āϤ āĻ•āϰāĻž āϝāĻžāĻŦ⧇
āĻĢāĻ¨ā§āϟ, āĻ•āϞāĻžāĻŽ, āĻĄāĻŋāĻ­āĻžāχāĻĄāĻžāϰ
āĻĒā§āϰāĻļā§āύ/āĻ…āĻĒāĻļāύ āĻ¸ā§āϟāĻžāχāϞ āĻĒāϰāĻŋāĻŦāĻ°ā§āϤāύ
āϏ⧇āϟ āϕ⧋āĻĄ, āĻŦāĻŋāώāϝāĻŧ āϕ⧋āĻĄ
āĻāĻ–āύāχ āĻļ⧁āϰ⧁ āĻ•āϰ⧁āύ āĻĄā§‡āĻŽā§‹ āĻĻ⧇āϖ⧁āύ
ā§Ģā§Ļ,ā§Ļā§Ļā§Ļ+
āĻļāĻŋāĻ•ā§āώāĻ•
ā§Šā§Ļ āϞāĻ•ā§āώ+
āĻĒā§āϰāĻļā§āύāĻĒāĻ¤ā§āϰ

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āĻŽāĻžāĻ¤ā§āϰ ā§§ā§Ģ āĻĒ⧟āϏāĻžā§Ÿ āĻĒā§āϰāĻļā§āύāĻĒāĻ¤ā§āϰ
ā§§ āĻ•ā§āϞāĻŋāϕ⧇ āĻĒā§āϰāĻļā§āύ, āĻļā§€āϟ, āϏāĻžāĻœā§‡āĻļāύ āϤ⧈āϰāĻŋ āĻ•āϰ⧁āύ āφāϜāχ

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