The perimeter of a square is equal to the perimeter of rectangle. The length of the rectangle is three times longer than its width having total area of 1,200 sq meters. What will be the total cost if the total area of the square is covered is covered with stones having a dimension of 50 centimeter square each and if Tk. 50 is charged for placing as stone in the square?

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Satt Academy · Accepted Answer

Let, width of the rectangle be x meterLength of the rectangle be 3x meterAccording to question,

3x×x=1,200 ⇒3x2=1,200 ⇒x2= 1,2003 x2=400 ∴x= 400 x=202 x=20 The perimeter of rectangle will be 2 [3×20+20=260+20=2×80=160 meterPerimeter of the square, 4a=160 One side of the square will be 40 meterArea of the square will be = (40 x 40) = 1,600m2 Now, length of 1 stone is 50cm =, 50100=0.5 m  Area of one stone will be = (0.5x0.5)=0.25 m²Number of stone required to cover the square = 1,600+0.25=6,400 piecesTotal amount of taka required at 50 tk per stone is 6,400 × 50 = 3,20,000  Tk. ans.]

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