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একটি বৈদ্যুতিক পাখা প্রতি মিনিটে 90 বার ঘুরছে। এর কৌণিক বেগ কত হবে?

Created: 1 year ago | Updated: 1 year ago

Updated: 1 year ago

\frac{π}{3} r a d s^{- 1}

3 π r a d s^{- 1}

90 π r a d s^{- 1}

180 π r a d s^{- 1}

ব্যাখ্যা

517

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\vec{A} . \vec{B}

\vec{C}

20 Ω

1.6 \times 10^{- 19} C

9.11 \times 10^{- 31} k g

S = \frac{1}{3} t^{3} + 3 t

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