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1. If x and y are positive integers, each greater than 1, and if 13(x-1)= 17(y-1), what is the least possible value of (x+y)?

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13(x-1)=17(y-1)

X-1/y-1=17/13

x-1+y-1/x-1-y+1=17+13/17-13

X+y-2/x-y=30/4

X+y-2=30. X-y=4

X+y=32

Ans.32

Created: 3 months ago | Updated: 2 months ago

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