Rahim can do a piece of work in 80 days. Rahim works for 10 days and Karim alone finishes the rest of the work in 42 days. How much time would it take for the two them together to complete the whole work? (Unitary method)

Created: 1 year ago | Updated: 1 year ago

Updated: 1 year ago

Rahim can do in 80 days = 1 work

Rahim can do in 1 days = $\frac{1}{80}$ part of work

Rahim can do in 10 days= $\frac{10}{80} = \frac{1}{80}$ part of work

Remaining work= $1 - \frac{1}{8} = \frac{7}{8}$ part of work

Again, Karim can do $\frac{7}{8}$ part in 42 days.

Karim can do 1 part= $\frac{42 \times 8}{7} = 48$ days

Karim can do in 1 day = $\frac{1}{48}$ part of work

(Rahim + Karim) can do in 1 day = $\frac{1}{80} + \frac{1}{48} = \frac{3 + 5}{240} = \frac{1}{30}$

So, Rahim + Karim can do the work in 30 days, ans.

1 year ago

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