In a group of 15, 7 can speak Spanish , 8 can speak French and 3 can speak neither . What fracton of the group can speak both French and spanish?
-
ক
1/5
-
খ
4/15
-
গ
1/3
-
ঘ
7/156
To find the fraction of the group that can speak both French and Spanish, you can use the principle of inclusion-exclusion.
Given:
- Total number in the group (n) = 15
- Number who can speak Spanish (S) = 7
- Number who can speak French (F) = 8
- Number who can speak neither (N) = 3
You want to find the fraction who can speak both French and Spanish (denoted as FS).
First, find the fraction who can speak either French or Spanish or both: Fraction who can speak French or Spanish = (S + F - FS) / n
Now, you know that 3 people can speak neither, so: Fraction who can speak French or Spanish = (S + F - FS) / n = (7 + 8 - FS) / 15 = (15 - FS) / 15
Since you want to find the fraction who can speak both French and Spanish, you need to subtract the fraction who can speak either French or Spanish from 1 (because everyone falls into one of these categories, so the sum of their fractions should equal 1):
1 - Fraction who can speak either French or Spanish = 1 - [(15 - FS) / 15] = (15/15) - (15 - FS) / 15 = (15 - 15 + FS) / 15 = FS / 15
So, the fraction of the group that can speak both French and Spanish (FS) is FS / 15.
Now, you're given that this fraction is equal to 1/5:
FS / 15 = 1/5
To find FS, multiply both sides by 15:
FS = (1/5) * 15 = 3
So, the fraction of the group that can speak both French and Spanish is 3/15, which simplifies to 1/5.
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