Rashid can do a piece of work in 8 days, which Tipu can finish in 12 days. If they work at it on alternate days with Rashid beginning, in how many days, the work will be finished?

Rashid  =  $\left(\frac{1}{8}\right)$ work/day
Tipu  =  $\left(\frac{1}{12}\right)$ work/day
Together এদের work rate  =  ($\frac{1}{8}$  +  $\frac{1}{2}$)  =  $\frac{5}{24}$ (work/day)
তাহলে তাদের লাগবে, (24/5) day/work  =  4.8 days to finish one work
But দুজন alternate day তে কাজ করবে, তাহলে twice সময় লাগবে  -  4.8  ×  2  =  9.6 days
   =  $\frac{19}{2}$ Days

Rashid  =  $\left(\frac{1}{8}\right)$ work/day Tipu  =  $\left(\frac{1}{12}\right)$ work/day Together এদের work rate  =  ($\frac{1}{8}$  +1/12  )  = $\frac{5}{24}$ (work/day) তাহলে তাদের লাগবে, (24/5) day/work  =  4.8 days to finish one work But দুজন alternate day তে কাজ করবে, তাহলে twice সময় লাগবে  -  4.8  ×  2  =  9.6 days   =  $\frac{19}{2}$ Days