The perimeter of a square field is equal to the perimeter of a rectangular field. Length of the rectangular is 3 times of its width and the area is 768 square meter. How many square sized tiles of 80 centimeter width will be required to cover the square field?

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Satt Academy · Accepted Answer

Let,Width(W) of Rectangular =xLength(L) of Rectangular=3xSo, Rectangular area=3x×x=3x^2ATQ, 3x^2=768x^2=256x=16Now,Rectangular Perimeter,=2(L+W)=2(3x+x)=8x=8×16=128Rectangular perimeter =Square perimeter so, Square perimeter,4x=128x=32Area of square=x^2=32×32=1024 Need total tiles=1024÷(.8×.8)=1600 Pieces.

The perimeter of a square field is equal to the perimeter of a rectangular field. Length of the rectangular is 3 times of its width and the area is 768 square meter. How many square sized tiles of 80 centimeter width will be required to cover the square field? (Geometry (rectangle))

Question: The perimeter of a square field is equal to the perimeter of a rectangular field. Length of the rectangular is 3 times of its width and the area is 768 square meter. How many square sized tiles of 80 centimeter width will be required to cover the square field? (Geometry (rectangle))

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