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All Written Question - (3488)

Y=√3+√2 1/y= 1/√3+√2= 1(√3-√2)/(√3+√2)(√3-√2) =√3-√2

y-1/y=√3+√2-√3+√2= 2√2 

Now, (y2+1/y2)(y3-1/y3)

={(y-1/y)2+ 2.y.1/y}{(y-1/y)3+ 3.y.1/y(y-1/y)}

={(2√2)^2+ 2} { (2√2)^3+3(2√2)}

=(8+2)(16√2+6√2)

=10×22√2

=220√2 (ans)

2 months ago